MicrobiologyBytes: Maths & Computers for Biologists: Areas & Volumes Updated: October 19, 2004 Search

Areas and Volumes

Further information on this topic can be found in Chapter 5 of:

CoverMaths from Scratch for Biologists

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Geometry is the branch of mathematics that deals with the properties of space and objects. It is one of the oldest branches of mathematics, named from Greek for "Earth measurement".

Trigonometry is the branch of mathematics concerned with specific functions of angles and their application to calculations in geometry.

TWO-DIMENSIONAL SHAPES: PERIMETER: AREA:
Square:

square

4 x x2
Rectangle:

rectangle

2 (x + y) x y
Circle:

circle

2 p r

 

(p * d)

p r2
Ellipse:

ellipse

p (1.5 (x + y) - sqrt(x * y)) p x y
Triangle (any):

triangle

x + y + z 0.5 z h
Triangle (right-angled):

triangle

x + y + z 0.5 x y
THREE-DIMENSIONAL OBJECTS: SURFACE AREA: VOLUME:
Cube:

cube

6 x2 x3
Cubeoid:

cubeoid

2 (x y) + 2 (x z) + 2 (y z) x y z
Sphere:

sphere

4 p r2

4 p r3 / 3

or

4/3 p r3

Ellipsoid:

ellipsoid

No simple formula! 4 p r x y / 3
Cylinder:

cylinder

2 p r h + 2 p r2 p r2 h
Cone / Pyramid:

cone pyramid

0.5 p h + b b h / 3

Calculations involving simple geometric shapes are usually straightforward (except for ellipsoids!) - use the formulae above.

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There are few straight lines in biology.

In biology, most shapes are complex but are either:

  • Approximations of simple shapes

    or

  • Combinations of simple shapes

Therefore, to determine shapes and volumes in biology, it is necessary to devise a strategy by which to approach the problem. The following examples illustrate SOME possible approaches:

Example 1:

A tissue is composed of cells which are roughly spherical in shape and about 45 µm in diameter.
Calculate the total number of cells present in 1 cm3 of this tissue.

Strategy:

  1. Calculate the volume of a single cell.
  2. Calculate the number of µm3 in 1 cm3 of tissue.
  3. Calculate the number of cells in 1 cm3 of tissue.

a) Volume of a sphere = 4/3 p r3

Volume of each cell = 4/3 p 22.53 µm3 = 47713 µm3

b) 1cm = 10,000 µm

1 cm3 = 104 * 104 * 104 = 1012 µm3

c) Number of cells in 1 cm3 = 1012 / 47713 = 20958648 = 2.09*107

 

Example 2:

Fibroblast cells like the one below are cultured on circular coverslips 10 mm in diameter, and have a doubling time of 24 hrs.

cellIf you have a coverslip with 1000 cells on it, how long will it take for these cells to multiply to give a confluent culture covering the whole of the coverslip?

Strategy:

  1. Calculate the area of the coverslip in µm2.
  2. Calculate the area of a single cell, assuming the cells are triangular.
  3. Calculate how many cells would cover the whole of the coverslip.
  4. Calculate how long it will take for 1000 cells to multiply to give the required number.
a) Area of coverslip = p r2 = 78.5 mm2 = 7.85*107 µm2

b) Area of cell = 0.5 z h = 0.5 * 45 * 15 = 338 µm2

c) 7.85*107 / 338 = 2.32*105 cells required to cover the coverslip.

d) By repeatedly multiplying 1000 by 2, it would take about 9 days for the original 1000 cells to cover the coverslip:

 

Day 1:
Day 2:
Day 3:
Day 4:
Day 5:
Day 6:
Day 7:
Day 8:
Day 9:
1*103
2*103
4*103
8*103
1.6*104
3.2*104
6.4*104
1.28*105
2.56*105

 

Are all the assumptions made valid?

 

Example 3:

ArabidopsisAn Arabidopsis seedling has a root system which weighs 1.5 grams. The average diameter of the roots is 0.2 mm.

Calculate the total length and surface area of the root system.

Assume: The roots have the same density as water, each root is a cylinder with a constant radius and the root tips have a negligible volume.

Strategy:

  1. Calculate the volume of the root system.
  2. Calculate the total root length.
  3. Calculate the surface area.
a) Density = weight/volume  therefore  volume = weight/density

= 1.5 g / 1 g mL-1 = 1.5 mL

b) Volume of a cylinder: V = p r2 h

Therefore length of a cylinder: h = V / p r2

h = 1.5 / p * 0.01 cm2

= 47.8 cm = 0.0478 m

c) Surface area of a cylinder = 2 p r h (ignoring the ends)

= 2 p (0.01 cm2) 47.8 cm

= 3 cm2

Are all the assumptions made valid?


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